2018 Macau Masters
The 2018 Macau Masters was a non-ranking team and six-red snooker variant invitational event that took place on 24 and 25 October 2018.[2] The event's team event was made up of two teams of four, competing in six games, with Team B defeating Team A with a score of 5–1.[3] The event's six red singles knockout tournament was won by Barry Hawkins. Prize FundThe event had a total prize fund of $100,000 awarded as follows:[4] Team event
Six-red event
Tournament teamsThe event was made up of two teams of four, with players playing in six "best of 5" frames matches. Frames 1, 3 and 5 were doubles matches, whereas frames 2 and 4 were alternate singles.[5][6][7]
ResultsTeam eventThe team event saw both teams field teams of two for individual team matches. Each player could only play with a partner for one match during the event.[8]
Six-red eventTo finish the event, the 6 Reds Leapfrog Challenge took place.[1] All 8-players played in a "killer" style match, with players required to win their match to continue on a winner stays on basis. The players were drawn based on world rankings.[9] All matches were first to one frame of 6-red snooker, with the final being a best of 5 frame 6-red match.[10]
References
Information related to 2018 Macau Masters |
Portal di Ensiklopedia Dunia